Zwei-Erzeuger Untergruppen von PSL(2,R)
The algorithms explained in
- "The constructive membership problem for discrete free subgroups of SL(2,R)"
- "The constructive membership problem for discrete two-generator subgroups of SL(2,R)"
have been implemented in Magma and can be downloaded here.
How to use this file with Magma:
The above package has to be loaded into your Magma workspace using:
Constructing a two-generator subgoup
Suppose A, B are matrices over K. To generate the group G:= <A, B> as a subgroup of (P)SL(2,R) one uses the commands TwoGeneratorSubgroupSL2R and TwoGeneratorSubgroupPSL2R. Besides the matrices A and B they also expect an embedding of K into R as a third parameter. If K is the field of rationals, one has to use Infinity() as embedding.
> A:= Matrix(2, [ 2, 0, 2, 1/2 ]); > B:= Matrix(2, [ 5, 2, -3, -1 ]); > G:= TwoGeneratorSubgroupSL2R(A, B, Infinity()); G; Two generator subgroup of SL(2,R) generated by [ 2 0] [ 2 1/2], [ 5 2] [-3 -1]
Predicates of two-generator subgoups
The generators of G can be accessed as G.1 and G.2. The following functions
can be used to decide if G is discrete, etc. In the example above,
> IsDiscreteAndFree(G); true
So the group G is discrete and free.
Constructive membership for two-generator subgoups
Whenever the group G is discrete, the membership problem can be decided using the Membership intrinsic. In the example above,
> Membership(G, A^10 * B^3 * A); true $.1^10 * $.2^3 * $.1 > Membership(G, -A); false
The first return value indicates whether the element is in G. If this is the case, then the second return value is a word in a free group of rank 2 that expresses the element in the generators of G. Note that if G was created as a subgroup of PSL(2,R) then the second membership test above would yield true:
> H:= TwoGeneratorSubgroupPSL2R(A, B, Infinity()); > Membership(H, -A); true $.1
As explained in the papers mentioned in the beginning, the algorithm usually computes a witness pair for G. The chosen witness pair can be obtained using the WitnessPair intrinsic.
We construct a (2,3,7)-triangle group:
> K:= NumberField( Polynomial([-1, 0, -2, 0, 1, 0, 1]) ); > eta:= K.1^2; > X:= Matrix(K, 2, [0, -K.1, K.1^5 + K.1^3 - 2*K.1, 0 ]); > Y:= Matrix(K, 2, [1/2, 1/2*(-K.1^5 - K.1^4 - K.1^3 + K.1 + 1), 1/2*(-K.1^5 + K.1^4 + 3*K.1 - 2) , 1/2] ); > plc:= InfinitePlaces(K); > G:= TwoGeneratorSubgroupSL2R(X, Y, plc); > IsTriangleGroup(G); true <2, 3, 7>